3.2x^2+2.4x=5

Solution for 3.2x^2+2.4x=5 equation:

3.2x^2+2.4x=5

We move all terms to the left:

3.2x^2+2.4x-(5)=0

a = 3.2; b = 2.4; c = -5;
Δ = b2-4ac
Δ = 2.42-4·3.2·(-5)
Δ = 69.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{69.76}}{2*3.2}=\frac{-2.4-\sqrt{69.76}}{6.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{69.76}}{2*3.2}=\frac{-2.4+\sqrt{69.76}}{6.4}
$